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Forum Index : Electronics : Op-amp charge controller

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adonis
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Joined: 13/02/2010
Location: Sweden
Posts: 42
Posted: 06:16pm 19 Feb 2010
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if you go from high to low voltages, at what voltage does the op3 output go low?
 
adonis
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Posted: 06:20pm 19 Feb 2010
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im gonna put my kids to bed, will be back in 30min.
 
kalamidas
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Posted: 06:21pm 19 Feb 2010
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14,4v op3 is 1,43
 
adonis
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Posted: 06:44pm 19 Feb 2010
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ok. thats not right. is your 10k and 100k resistors connected correctly?
 
Bub73

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Posts: 116
Posted: 06:50pm 19 Feb 2010
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can you post a photo of your board ?

Also check the value and location of the 10k resistor and jumpers.

Bob
 
kalamidas
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Posted: 07:52pm 19 Feb 2010
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this is the photo
 
Bub73

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Posted: 08:31pm 19 Feb 2010
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I don't see one of the jumpers for paralleling the pots, are they both there ?

I'll look closer later.

Bob
 
kalamidas
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Posted: 08:35pm 19 Feb 2010
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it is there under the silicon right side of the low volt trimmer
 
adonis
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Posted: 08:40pm 19 Feb 2010
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sorry, my kids refuse to fall asleep. but here is perhaps a small explanation to help you troubleshoot. the problem seems to lie in the feedbackloop in OP3, the signals from OP1 and 2 seems to be ok, so the trimpots, R1 and R2 is probably working as they should.

the purpose of the 10k in series with the 100k is to keep OP3 high until a high signal from OP2 turns it low.
when the voltages is between 12 and 15 volt both OP1 and 2 are low, and the diod (4001) makes sure that OP3 stays low if it already is low.
if it is high, (as it is when the voltages drops from above 15V) the resistors in series keeps it high.
the potential between the two resistors should be Vop3out*(100/110) and this is also what OP3+in sees. this is not the case in your controller, so there might be a problem in this resistor pair, or in their surrounding connections.

hope this helps.
 
kalamidas
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Posted: 08:46pm 19 Feb 2010
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thanks for your time ,i hope i didnt keep you away from your kids, after all they have priority.
i will check the resistors and the surroundings.
 
Bub73

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Posted: 09:25pm 19 Feb 2010
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Yes adonis is right on op3; check the values of the resistors with your ohms meter a mismarked resisitor could cause no end of trouble here and on the bd139 as well.

Bob
 
adonis
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Posted: 09:54pm 19 Feb 2010
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no worries, i gave them priority. hope you get it together!
 
Downwind

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Joined: 09/09/2009
Location: Australia
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Posted: 11:56pm 19 Feb 2010
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I have a few questions about the board as its a bit hard to see clearly.




1...looks incorrect to me(solder bridge??)
2...What is the combined resistance of R1 here.
3...What value is this resistor as it looks like 1K and should be 10K
...................................................

What voltages do you have on pins 5,6,7 as looks to be something wrong with op2 voltage, as when op1 (pin1) goes low the relay switches off.

This would indicate op2 (pin7) was high, at the time op1 goes low.

Op2 should be low (1.2 -1.5v) and go high when the voltage is around 12v or adjusted to suit.
You will need to check op2 voltage and get that to be high at 12 volts and go low at about 0.2 volts above 12v.
This not happening so no hysterisis.


Pete

Sometimes it just works
 
Bub73

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Posted: 01:04am 20 Feb 2010
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I also noticed you did not use a socket for the ic, so I must ask what type of iron and heat settings you used when soldering on the chip itself especially if you have tried more than one.

Bob
 
kalamidas
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Posted: 07:18pm 20 Feb 2010
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hello again and thamks for your questions shows that you game me some time.

answers
Bob i used standard solder and a 60 watt solderind device(i dont know the english word for it).
in this bord i did not tried other ic's.
i tried them on the second board atemting to debug the board

Pete
1 i just cut the resistor and test the resistanse and then resolder it again it seems that is bridged but it is not i left some of the wire and it is above the other resistor show it seems like a bridge.

2.the combined resistance on my multimeter is 10,2k oms
an 8k and a 2,2k

3 10k the last one i had it has a thiker red line, 3 times check on my multimeter .

I will leave this bord for the time and i will try again with a new one.so i can cross check the two boards.for the hysterisis problem i will just power the controller from the windmill not the bateries.
what do you thing about that?
 
Bub73

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Posted: 08:06pm 20 Feb 2010
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Use a socket this time for the ic they are cheap or even a used one if you have some junk around; this will keep the heat and possible static from your soldering iron off the chip itself and make it easy to swap out chips without damage.

Then install the chip tl084 last.

You also need some type of varible power supply to set the high and low pots; using the windmill alone may let the magic smoke out.

BobEdited by Bub73 2010-02-22
 
Downwind

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Posted: 12:48am 21 Feb 2010
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I dont think i would power the board from the windmill only, as the voltage may well exceed the chips rating.

Pete.
Sometimes it just works
 
adonis
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Joined: 13/02/2010
Location: Sweden
Posts: 42
Posted: 06:46am 21 Feb 2010
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i previously suggested to use smaller resistors before the led:s. this might be a bad idea since the tl084 is not built for very large output currents. could someone with more knowlige tell us if this would burn the chip?

/jonathan
 
kalamidas
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Posts: 21
Posted: 08:50am 21 Feb 2010
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this is the third board and this is the readouts
12v 13.5v 15v
0.61 1 14 6.46 0.61 1 14 6.46 0.61 1 14 6.45
3.53 2 13 3.92 3.71 2 13 3.94 3.89 2 13 3.34
2.83 3 12 5.90 3.21 3 12 5.90 3.47 2 12 5.90
7.89 4 11 0.01 7.89 4 11 0.01 7.89 4 11 0.01
2.85 5 10 0.01 3.21 5 10 0.01 3.47 5 10 0.01
2.86 6 9 7.10 3.21 6 9 7.32 3.47 6 9 7.32
7.10 7 8 590 7.28 7 8 5.90 7.32 7 8 5.90
 
kalamidas
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Posts: 21
Posted: 08:54am 21 Feb 2010
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12v 13.5v 15v
0.61 =1 14= 6.46 0.61= 1 14 =6.46 0.61 =1 14= 6.45
3.53= 2 13= 3.92 3.71= 2 13= 3.94 3.89= 2 13 =3.34
2.83= 3 12 =5.90 3.21= 3 12= 5.90 3.47=3 12= 5.90
7.89 =4 11= 0.01 7.89= 4 11= 0.01 7.89 =4 11= 0.01
2.85= 5 10= 0.01 3.21 =5 10= 0.01 3.47 =5 10= 0.01
2.86= 6 9= 7.10 3.21 =6 9= 7.32 3.47= 6 9= 7.32
7.10 =7 8= 590 7.28 =7 8= 5.90 7.32= 7 8= 5.90
 
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